Answer by Milo Brandt for Particular case of every sequence has a Cauchy...
The proof works in $\mathbb{R}^n$ under the usual metric (from the Bolzano-Weierstrass theorem), but fails in general. In particular, it conflates "bounded" with "compact", which is, in general, not...
View ArticleParticular case of every sequence has a Cauchy subsequence?
A metric space (X,d) has the following property:Given $\epsilon >0$ and non-empty finite subset $X_\epsilon \subset X$$$ \inf \{ d(x,p) : p \in X_\epsilon \} < \epsilon$$for $x \in X$I would like...
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